Leetcode - Count Odd Numbers in an Interval Range

Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).

Example 1:

Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].

Example 2:

Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].

Solution,#

생각하지 않고 풀었다.

class Solution {
    public int countOdds(int low, int high) {
        if (low % 2 == 0) low += 1;
        if (high % 2 == 0) high -= 1;
        
        if (high - low == 0) return 1;
        return ((high - low) / 2) + 1;
    }
}